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Question:
Find (-i)^4n+3; if n is an integer
Answer:

Given (-i)4n+3 ,where n is an integer.

Let A = (-i)4n+3

=> A = (-i)4n * (-i)3

=> A = (i)4n * (-i)3

=> A = -(i)4n * i3 

=> A = -i3     {since i4 = 1}

=> A = -i * i2    

=> A = -i * (-1)     {since i2 = -1}

=> A = i

So, the value of (-i)4n+3 is i

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